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Re: [WM]: 8x8 blocks



hi
the image is divided into 8x8 blocks coz

1.if the image is taken as it is (256x256) and DCT transformed, then the computational complexity will increase.

2.It is found that there is a relation between neighbouring consecutive pixels (about 16 pixels). 

After practical implementation it was found that 8x8 blocks are most suitable. So always 8x8 bolcks are taken.

Also the image is not to be divided in to 8x8 parts.
But the image is to be divided into 8x8 pixel blocks.
Each block is of size 8x8 pixels, and the image can hav many such blocks depending upon its size.

The explanation is as per my knowledge.
If wrong please correct me.



regards,
rajan
http://www.geocities.com/gwatermarker




--- SYMS! <syms21@yahoo.com> wrote:

> In doing DCT compression for DCT watermarking, it is first asked for 
> us to 'segment' the image into 8x8..what do ut means by that?
> 
> Another thing..anyone knows how to segment a 256x256 image into 8x8 
> using Matlab? i've tried it, but what i've got instead is the
> 8x8 pixel of the left most upper corner of he image..not having the 
> image devided into 8x8..
> 
> any help would be appreciated
> 


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